Hi~ o(*￣▽￣*)ブ 这两题，详细过程的，谢谢，有绝对好评！

[(x^2+4)/x-4]÷[(x^2-4)/(x^2+2x)]
=[(x^2+4)/x-4x/x]÷[(x+2)(x-2)/x(x+2)]
=[(x-2)^2/x]÷[(x-2)/x]
=(x-2)^2/x×x/(x-2)
=x-2

[(3x+4)/(x^2-1)-2/(x-2)÷(x+2)/(x^2-2x+1)]
=[(3x+4)(x-2)/(x^2-1)(x-2)-2(x^2-1)/(x^2-1)(x-2)]÷[(x+2)/(x-1)^2]
=(x^2-2x-6)/(x+1)(x-1)(x-2)×(x-1)^2/(x+2)
=