sax解析xml时遇到&符号怎么办

a.util.List;

import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;

import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;

public class SaxParseService extends DefaultHandler{
private List books = null;
private Book book = null;
private String preTag = null;//作用是记录解析时的上一个节点名称
/**
* 特殊字符数量很多时方法1显然不实用此时可用转义来实现
* < <本回答被提问者采纳