为什么我用nextInt会报错

package java.uyil;

//import java.util.Scanner;
import java.util.*;
//import java.

public class Scanner {

public static void main(String[]args){
Scanner scanner= new Scanner();

System.out.print("请输入学生年龄:");
int ageOfStudent = scanner.nextInt();
System.out.println("该生是否满18岁?"+
(ageOfStudent>=18?"yes":"no"));

}
}
package java.uyil;

//import java.util.Scanner;
import java.util.*;
//import java.

public class Test {

public static void main(String[]args){
Scanner scanner= new Scanner(System.in);

System.out.print("请输入学生年龄:");
int ageOfStudent = scanner.nextInt();
System.out.println("该生是否满18岁?"+
(ageOfStudent>=18?"yes":"no"));

}
}

需要修改package 里面的java, 关键字不能用在包名
Scanner scanner= new Scanner(System.in);你要输入整数才可以

package java1.a;

//import java.util.Scanner;
import java.util.*;
//import java.

public class Test {

public static void main(String[]args){
Scanner scanner= new Scanner(System.in);

System.out.print("请输入学生年龄:");
int ageOfStudent = scanner.nextInt();
System.out.println("该生是否满18岁?"+
(ageOfStudent>=18?"yes":"no"));

}
}追问

提示编辑器不包含一个主要类型

追答

包名java1.a

你用下面这个代码吧
package java1.a;

import java.util.*;

public class Test {

public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);

System.out.print("Please input the age for a student:");
int ageOfStudent = scanner.nextInt();
System.out.println("Is greater than 18?"+ (ageOfStudent >= 18 ? "yes" : "no"));

}
}

温馨提示:内容为网友见解,仅供参考
第1个回答  2012-06-14
public class Test {
public static void main(String[]args){
Scanner scanner= new Scanner(System.in);
System.out.print("请输入学生年龄:");
int ageOfStudent = scanner.nextInt();
System.out.println("该生是否满18岁?"+
(ageOfStudent>=18?"yes":"no"));

}
}

顺带注意类名本回答被网友采纳
第2个回答  2012-06-14
Scanner scanner= new Scanner(System.in);追问

加了 Scanner scanner= new Scanner(System.in); 这条也报错啦!

追答

把你这类名改一下。。和Scanner重名了

第3个回答  2012-06-14
Scanner scanner= new Scanner(System.in);
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