我在matlab中输入如下:
>> syms x y xp yp xi yi min;
>> f1='(x-xp)^2+(y-yp)^2=min^2';
>> f2='(x-xi)^2+(y-yi)^2=3*min^2';
>> [x,y]=solve(f1,f2)
求解的结果是x =
xp+(-yp^2+min^2-y^2+2*y*yp)^(1/2)
xp+(-yp^2+min^2-y^2+2*y*yp)^(1/2)
xp-(-yp^2+min^2-y^2+2*y*yp)^(1/2)
xp-(-yp^2+min^2-y^2+2*y*yp)^(1/2)
y=
xp+(-yp^2+min^2-y^2+2*y*yp)^(1/2)+(2*y*yi-yi^2+3*min^2-y^2)^(1/2)
xp+(-yp^2+min^2-y^2+2*y*yp)^(1/2)-(2*y*yi-yi^2+3*min^2-y^2)^(1/2)
xp-(-yp^2+min^2-y^2+2*y*yp)^(1/2)+(2*y*yi-yi^2+3*min^2-y^2)^(1/2)
xp-(-yp^2+min^2-y^2+2*y*yp)^(1/2)-(2*y*yi-yi^2+3*min^2-y^2)^(1/2)
x和y应该只有两组解,怎么出来四组了呢?更大问题是x,y的表达式中还含有x,y本身,请问各位这是怎么回事啊?谢谢