[a,c]=solve('(-0.73*tan(0.31*c)+1.66)/(0.56*tan(0.31*c)+0.478)=tan(0.3*a-1.8)','0.475*cot(0.48*a)+1.44*cot(0.5*c)+0.77*cot(0.48*a)*cot(0.5*c)=1')
fplot(@humps,[-5 5])
eee
Warning: Explicit solution could not be found.
> In solve at 140
a =
[ empty sym ]
c =
[]
刚刚搞错啦,是这样的:[a,c]=solve('(-0.73*tan(0.31*c)+1.66)/(0.56*tan(0.31*c)+0.478)=tan(0.3*a-1.8)','0.475*cot(0.48*a)+1.44*cot(0.5*c)+0.77*cot(0.48*a)*cot(0.5*c)=1')
Warning: Explicit solution could not be found.
> In solve at 140
a =
[ empty sym ]
c =
[]
能不能用二分法求解近似值呢?
有什么方法解这个方程组啊?solve('(-0.73*tan(0.31*c)+1.66)/(0.56*tan(0.31*c)+0.478)=tan(0.3*a-1.8)','0.475*cot(0.48*a)+1.44*cot(0.5*c)+0.77*cot(0.48*a)*cot(0.5*c)=1')