我在eclipse里用Java编了一个Servlet的下程序 总是报
HTTP Status 404 - /JD6/servlet/zxc.TestServlet
--------------------------------------------------------------------------------
type Status report
message /JD6/servlet/zxc.TestServlet
description The requested resource is not available.
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Apache Tomcat/7.0.69
希望大神帮忙
我的代码package zxc;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.PrintWriter;
public class TestServlet extends HttpServlet {
public TestServlet() {
super();
}
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
PrintWriter pw=response.getWriter();
pw.println("hello");
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
doGet(request, response);
}
}
1.输入的地址有误（应用名大小写不正确，名称拼写不正确）
2.在web.xml文件中<servlet>和<servlet-mapping>中的两个<servlet-name>不一致
3.没有将工程部署到Tomcat的webapps下面
4.Web工程部署时的结构没有遵循Servlet的规范追问
我的WebContent下的WEB—INF下怎么没有web.xml文件
