关于matlab中solve函数求解方程组的问题，代码如下，而显示结果如图所示，为什么。我用的版本R2013a

[b,F,f,phi]=solve('a(1-a*F)-b*(1+b)*lambda_r^2,phi-atan((1-a)/((1+b)*lambda_r)),f-B/2*(R-r)/R*sin(phi),F-2/pi*acos(exp(-f))')

我的版本是2012a。（注：solve求解得到表达式）
结果如下：
b =

-log(cos((pi*F)/2))
-log(cos((pi*F)/2))

F =

-a(1 - F*a)^(1/2)/(b^(1/2)*(b + 1)^(1/2))
a(1 - F*a)^(1/2)/(b^(1/2)*(b + 1)^(1/2))

f =

atan((b^(1/2)*(a - 1))/(a(1 - F*a)^(1/2)*(b + 1)^(1/2)))
-atan((b^(1/2)*(a - 1))/(a(1 - F*a)^(1/2)*(b + 1)^(1/2)))

phi =

(2*R*a(1 - F*a)^(1/2)*(log(cos((pi*F)/2)) + (B*b^(1/2)*(a - 1))/(2*a(1 - F*a)^(1/2)*((b*(a - 1)^2)/(a(1 - F*a)*(b + 1)) + 1)^(1/2)*(b + 1)^(1/2)))*((b*(a - 1)^2)/(a(1 - F*a)*(b + 1)) + 1)^(1/2)*(b + 1)^(1/2))/(B*b^(1/2)*(a - 1))
-(2*R*a(1 - F*a)^(1/2)*(log(cos((pi*F)/2)) - (B*b^(1/2)*(a - 1))/(2*a(1 - F*a)^(1/2)*((b*(a - 1)^2)/(a(1 - F*a)*(b + 1)) + 1)^(1/2)*(b + 1)^(1/2)))*((b*(a - 1)^2)/(a(1 - F*a)*(b + 1)) + 1)^(1/2)*(b + 1)^(1/2))/(B*b^(1/2)*(a - 1))

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